What is ln(8/(3.14^2)*((230-50))/((65-50))) ?

The solution to ln(8/(3.14^2)*((230-50))/((65-50))) is ln(8)-2ln(3.14)++ln(230-50)-ln(65-50)

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simplify ln(8/(3.14^2)*((230-50))/((65-50)))

simplify

ln (\frac{8}{3.1 4 ^{2}} \cdot \frac{( 230 - 50 )}{( 65 - 50 )})

ln (8) - 2 ln (3.14) + + ln (230 - 50) - ln (65 - 50)

Decimal Notation

2.27590 \dots

Solution steps

ln (\frac{8}{3.1 4 ^{2}} \cdot \frac{( 230 - 50 )}{( 65 - 50 )})

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

ln (\frac{8}{3.1 4 ^{2}} \cdot \frac{( 230 - 50 )}{( 65 - 50 )}) = ln (\frac{8}{3.1 4 ^{2}}) + ln (\frac{( 230 - 50 )}{( 65 - 50 )})

= ln (\frac{8}{3.1 4 ^{2}}) + ln (\frac{( 230 - 50 )}{( 65 - 50 )})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{8}{3.1 4 ^{2}}) = ln (8) - ln (3.1 4^{2}), ln (\frac{230 - 50}{65 - 50}) = ln (230 - 50) - ln (65 - 50)

= ln (8) - ln (3.1 4^{2}) + + ln (230 - 50) - ln (65 - 50)

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

ln (3.1 4^{2}) = 2 ln (3.14)

= ln (8) - 2 ln (3.14) + + ln (230 - 50) - ln (65 - 50)

9.28 + lo g_{10} (\frac{0.15}{0.3})

lo g_{6} (x^{6}) - lo g_{6} (2 x^{2}) - lo g_{6} (x^{3})

ln (\frac{x ^{8} x ^{2} + 6}{( x + 6 ) ^{3}})

ln (\frac{27}{4}) - 1

x^{2} - \frac{13}{6} ln ∣ x + 2 ∣ + \frac{19}{6} ln ∣ x - 4 ∣ + 4

What is ln(8/(3.14^2)*((230-50))/((65-50))) ?
The solution to ln(8/(3.14^2)*((230-50))/((65-50))) is ln(8)-2ln(3.14)++ln(230-50)-ln(65-50)