What are the solutions to the equation 2x^2-20x+50=0 ?

The solutions to the equation 2x^2-20x+50=0 are x=5

Find the zeros of 2x^2-20x+50=0

The zeros of 2x^2-20x+50=0 are x=5

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2 x^{2} - 20 x + 50 = 0

x = 5

Solution steps

2 x^{2} - 20 x + 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 2 \cdot 50}{2 \cdot 2}

(- 20)^{2} - 4 \cdot 2 \cdot 50 = 0

x_{1, 2} = \frac{- ( - 20 ) \pm 0}{2 \cdot 2}

x = \frac{- ( - 20 )}{2 \cdot 2}

\frac{- ( - 20 )}{2 \cdot 2} = 5

x = 5

The solution to the quadratic equation is:

x = 5

x^{3} + 3 x^{2}

x^{2} - 6 < x

6 x^{2} + 13 x + 6 = 0

4 v^{2} = - 20 v

4 x^{4} - 24 x^{3} + 36 x^{2}

What are the solutions to the equation 2x^2-20x+50=0 ?
The solutions to the equation 2x^2-20x+50=0 are x=5
Find the zeros of 2x^2-20x+50=0
The zeros of 2x^2-20x+50=0 are x=5