What is ln((e^x+e^{-x})/(e^x-e^{-x)}) ?

The solution to ln((e^x+e^{-x})/(e^x-e^{-x)}) is ln(e^x+e^{-x})-ln(e^x-e^{-x})

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simplify ln((e^x+e^{-x})/(e^x-e^{-x)})

simplify

ln (\frac{e ^{x} + e ^{- x}}{e ^{x} - e ^{- x}})

ln (e^{x} + e^{- x}) - ln (e^{x} - e^{- x})

Solution steps

ln (\frac{e ^{x} + e ^{- x}}{e ^{x} - e ^{- x}})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{e ^{x} + e ^{- x}}{e ^{x} - e ^{- x}}) = ln (e^{x} + e^{- x}) - ln (e^{x} - e^{- x})

= ln (e^{x} + e^{- x}) - ln (e^{x} - e^{- x})

ln (- a \cdot e)

7 lo g_{b} (z - 7) - 6 lo g_{b} (z + 7)

5 ln (5) - 3 ln (3)

ln (\frac{1 + e ^{x}}{1 - e ^{x}})

\frac{1}{6} (ln ∣ x ∣ - ln (x + 6))

What is ln((e^x+e^{-x})/(e^x-e^{-x)}) ?
The solution to ln((e^x+e^{-x})/(e^x-e^{-x)}) is ln(e^x+e^{-x})-ln(e^x-e^{-x})