What is 4.35+log_{10}(2/3) ?

The solution to 4.35+log_{10}(2/3) is 4.35+log_{10}(2)-log_{10}(3)

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simplify 4.35+log_{10}(2/3)

simplify

4.35 + lo g_{10} (\frac{2}{3})

4.35 + lo g_{10} (2) - lo g_{10} (3)

Decimal Notation

4.17390 \dots

Solution steps

4.35 + lo g_{10} (\frac{2}{3})

lo g_{10} (\frac{2}{3}) = lo g_{10} (2) - lo g_{10} (3)

= 4.35 + lo g_{10} (2) - lo g_{10} (3)

lo g_{2} (\frac{e ^{7 x}}{e ^{8 y}})

2 lo g_{5} (1.75) + lo g_{5} (16)

lo g_{e} (\frac{14}{121})

- ln (\frac{22}{78})

lo g_{10} (j^{4} k^{7})

What is 4.35+log_{10}(2/3) ?
The solution to 4.35+log_{10}(2/3) is 4.35+log_{10}(2)-log_{10}(3)