What is log_{10}((23.16)/(sqrt(2))) ?

The solution to log_{10}((23.16)/(sqrt(2))) is log_{10}(23.16)-1/2 log_{10}(2)

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simplify log_{10}((23.16)/(sqrt(2)))

simplify

lo g_{10} (\frac{23.16}{2})

lo g_{10} (23.16) - \frac{1}{2} lo g_{10} (2)

Decimal Notation

1.21422 \dots

Solution steps

lo g_{10} (\frac{23.16}{2})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{10} (\frac{23.16}{2}) = lo g_{10} (23.16) - lo g_{10} (2)

= lo g_{10} (23.16) - lo g_{10} (2)

lo g_{10} (2) = \frac{1}{2} lo g_{10} (2)

= lo g_{10} (23.16) - \frac{1}{2} lo g_{10} (2)

0.026 \cdot ln (\frac{0.4644}{8 \cdot 1 0 ^{- 16}})

lo g_{10} (5 \cdot 4 \cdot 3 \cdot 2 \cdot 1)

4 (lo g_{5} (y) - 2 lo g_{5} (z)) + 3 lo g_{5} (w)

ln (3) - ln (2) - 1

\frac{1}{2} ln (5 + 2) - \frac{1}{2} ln (5 + 0)

What is log_{10}((23.16)/(sqrt(2))) ?
The solution to log_{10}((23.16)/(sqrt(2))) is log_{10}(23.16)-1/2 log_{10}(2)