What is expand 1/4*ln(((x+1))/(x-1)) ?

The solution to expand 1/4*ln(((x+1))/(x-1)) is 1/4 (ln(x+1)-ln(x-1))

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expand 1/4*ln(((x+1))/(x-1))

expand

\frac{1}{4} \cdot ln (\frac{( x + 1 )}{x - 1})

\frac{1}{4} (ln (x + 1) - ln (x - 1))

Solution steps

\frac{1}{4} ln (\frac{( x + 1 )}{x - 1})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{( x + 1 )}{x - 1}) = ln ((x + 1)) - ln (x - 1)

= \frac{1}{4} (ln (x + 1) - ln (x - 1))

3 + lo g_{10} (\frac{0.7 - x}{x})

lo g_{2} ((x^{3} + 2) (x - 9)^{3})

n \cdot (35.2 \cdot ln (\frac{420}{293}) - 8.314 \cdot ln (\frac{2500}{500}))

lo g_{7} (\frac{3 x ^{4}}{y})

\frac{1}{7} ln ((x + 2)^{7}) + \frac{1}{2} ln (x) - ln (x^{2} + 3 x + 2) 2

What is expand 1/4*ln(((x+1))/(x-1)) ?
The solution to expand 1/4*ln(((x+1))/(x-1)) is 1/4 (ln(x+1)-ln(x-1))