What is 1/i (ln(2.414-0.011i)-ln(2.054-0.0423i)) ?

The solution to 1/i (ln(2.414-0.011i)-ln(2.054-0.0423i)) is -iln(1.17487…+0.01884…i)

Popular >

simplify 1/i (ln(2.414-0.011i)-ln(2.054-0.0423i))

simplify

\frac{1}{i} (ln (2.414 - 0.011 i) - ln (2.054 - 0.0423 i))

- i ln (1.17487 \dots + 0.01884 \dots i)

Solution steps

\frac{1}{i} (ln (2.414 - 0.011 i) - ln (2.054 - 0.0423 i))

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (2.414 - 0.011 i) - ln (2.054 - 0.0423 i) = ln (\frac{2.414 - 0.011 i}{2.054 - 0.0423 i})

= \frac{1}{i} ln (\frac{2.414 - 0.011 i}{2.054 - 0.0423 i})

Simplify

\frac{2.414 - 0.011 i}{2.054 - 0.0423 i} : 1.17487 \dots + 0.01884 \dots i

= \frac{1}{i} ln (1.17487 \dots + 0.01884 \dots i)

\frac{1}{i} = - i

= - i ln (1.17487 \dots + 0.01884 \dots i)

lo g_{10} (x) - \frac{1}{2} lo g_{10} (x^{2} + 8)

ln (\frac{5}{15})

ln (\frac{0.0141300000000 \dots}{v ^{1.8}})

ln (e^{3 x} (1 - 2 x)^{- 2})

ln (x) + v + ln (v - 1)

What is 1/i (ln(2.414-0.011i)-ln(2.054-0.0423i)) ?
The solution to 1/i (ln(2.414-0.011i)-ln(2.054-0.0423i)) is -iln(1.17487…+0.01884…i)