What is ln((0.0141300000000…)/(v^{1.8)}) ?

The solution to ln((0.0141300000000…)/(v^{1.8)}) is ln(0.01413…)-1.8ln(v)

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simplify ln((0.0141300000000…)/(v^{1.8)})

simplify

ln (\frac{0.0141300000000 \dots}{v ^{1.8}})

ln (0.01413 \dots) - 1.8 ln (v)

Solution steps

ln (\frac{0.01413 \dots}{v ^{1.8}})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{0.01413 \dots}{v ^{1.8}}) = ln (0.01413 \dots) - ln (v^{1.8})

= ln (0.01413 \dots) - ln (v^{1.8})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

ln (v^{1.8}) = 1.8 ln (v)

= ln (0.01413 \dots) - 1.8 ln (v)

ln (e^{3 x} (1 - 2 x)^{- 2})

ln (x) + v + ln (v - 1)

3 lo g_{10} (X) + 2 lo g_{z} (5) - lo g_{10} (y)

8 lo g_{8} (7) - 2 lo g_{8} (6)

lo g_{a} (\frac{7 x y ^{3}}{z ^{4}})

What is ln((0.0141300000000…)/(v^{1.8)}) ?
The solution to ln((0.0141300000000…)/(v^{1.8)}) is ln(0.01413…)-1.8ln(v)