What is log_{2}(x-3)+log_{2}(x-1) ?

The solution to log_{2}(x-3)+log_{2}(x-1) is log_{2}((x-3)(x-1))

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simplify log_{2}(x-3)+log_{2}(x-1)

simplify

lo g_{2} (x - 3) + lo g_{2} (x - 1)

lo g_{2} ((x - 3) (x - 1))

Solution steps

lo g_{2} (x - 3) + lo g_{2} (x - 1)

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

lo g_{2} (x - 3) + lo g_{2} (x - 1) = lo g_{2} ((x - 3) (x - 1))

= lo g_{2} ((x - 3) (x - 1))

ln (2) e^{- 6} + (- 2.268) \cdot ln (0.15)

lo g_{10} (525) 5

\frac{1}{2} ln (\frac{130}{100})

- lo g_{10} (1 \cdot 1 0^{- 1.75})

6.1 + lo g_{10} (\frac{24.5}{1.01})

What is log_{2}(x-3)+log_{2}(x-1) ?
The solution to log_{2}(x-3)+log_{2}(x-1) is log_{2}((x-3)(x-1))