What are the solutions to the equation 4w^2+12w-44=0 ?

The solutions to the equation 4w^2+12w-44=0 are w=(-3+sqrt(53))/2 ,w=-(3+sqrt(53))/2

Find the zeros of 4w^2+12w-44=0

The zeros of 4w^2+12w-44=0 are w=(-3+sqrt(53))/2 ,w=-(3+sqrt(53))/2

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4 w^{2} + 12 w - 44 = 0

w = \frac{- 3 + 53}{2}, w = - \frac{3 + 53}{2}

Decimal Notation

w = 2.14005 \dots, w = - 5.14005 \dots

Solution steps

4 w^{2} + 12 w - 44 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 4 ( - 44 )}{2 \cdot 4}

1 2^{2} - 4 \cdot 4 (- 44) = 453

w_{1, 2} = \frac{- 12 \pm 4 53}{2 \cdot 4}

Separate the solutions

w_{1} = \frac{- 12 + 4 53}{2 \cdot 4}, w_{2} = \frac{- 12 - 4 53}{2 \cdot 4}

w = \frac{- 12 + 4 53}{2 \cdot 4} : \frac{- 3 + 53}{2}

w = \frac{- 12 - 4 53}{2 \cdot 4} : - \frac{3 + 53}{2}

The solutions to the quadratic equation are:

w = \frac{- 3 + 53}{2}, w = - \frac{3 + 53}{2}

0 = x^{2} + 5 x + 8

y^{2} - 19 y = 0

x, x^{2} = 4 p y

x^{2} - 2 x = - x + 6

\frac{( 3 x - 1 ) ^{2}}{16} - (x - \frac{1}{4}) (x + \frac{1}{4}) = - \frac{7}{8}

What are the solutions to the equation 4w^2+12w-44=0 ?
The solutions to the equation 4w^2+12w-44=0 are w=(-3+sqrt(53))/2 ,w=-(3+sqrt(53))/2
Find the zeros of 4w^2+12w-44=0
The zeros of 4w^2+12w-44=0 are w=(-3+sqrt(53))/2 ,w=-(3+sqrt(53))/2