What are the solutions to the equation x^2-8x=-x ?

The solutions to the equation x^2-8x=-x are x=7,x=0

Find the zeros of x^2-8x=-x

The zeros of x^2-8x=-x are x=7,x=0

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x^{2} - 8 x = - x

x = 7, x = 0

Solution steps

x^{2} - 8 x = - x

Move

x

to the left side

x^{2} - 7 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 0 = 7

x_{1, 2} = \frac{- ( - 7 ) \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 7}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 7}{2 \cdot 1}

x = \frac{- ( - 7 ) + 7}{2 \cdot 1} : 7

x = \frac{- ( - 7 ) - 7}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 7, x = 0

x^{2} - 10 x - 4 = - 2 x - 4

A (x) = x (\frac{288 - 2 x}{2})

(2 x + 1) (4 x^{2} - 2 x + 1) - 1 = 1.6 x^{2} (5 x - 2)

9 x^{2} - 12 x + 5

x^{2} + 6 x + 1 = - 2 x + 1

What are the solutions to the equation x^2-8x=-x ?
The solutions to the equation x^2-8x=-x are x=7,x=0
Find the zeros of x^2-8x=-x
The zeros of x^2-8x=-x are x=7,x=0