What are the solutions to the equation (a-sqrt(3))^2=-10sqrt(3)+28 ?

The solutions to the equation (a-sqrt(3))^2=-10sqrt(3)+28 are a=5,a=-5+2sqrt(3)

Find the zeros of (a-sqrt(3))^2=-10sqrt(3)+28

The zeros of (a-sqrt(3))^2=-10sqrt(3)+28 are a=5,a=-5+2sqrt(3)

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(a - 3)^{2} = - 103 + 28

a = 5, a = - 5 + 23

Decimal Notation

a = 5, a = - 1.53589 \dots

Solution steps

(a - 3)^{2} = - 103 + 28

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

a - 3 = - 103 + 28 : a = 5

Solve

a - 3 = - - 103 + 28 : a = - 5 + 23

The solutions to the quadratic equation are:

a = 5, a = - 5 + 23

x, z = x^{2} y + x cos (y^{3} - 5)

8 x^{2} = 135

x^{2} + x - 27 = 5 x + 5

x, 3 x^{2} + 5 y^{2} = 0

x^{2} + 2 x - 4 = - 4

What are the solutions to the equation (a-sqrt(3))^2=-10sqrt(3)+28 ?
The solutions to the equation (a-sqrt(3))^2=-10sqrt(3)+28 are a=5,a=-5+2sqrt(3)
Find the zeros of (a-sqrt(3))^2=-10sqrt(3)+28
The zeros of (a-sqrt(3))^2=-10sqrt(3)+28 are a=5,a=-5+2sqrt(3)