What are the solutions to the equation x^2+x-27=5x+5 ?

The solutions to the equation x^2+x-27=5x+5 are x=8,x=-4

Find the zeros of x^2+x-27=5x+5

The zeros of x^2+x-27=5x+5 are x=8,x=-4

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x^{2} + x - 27 = 5 x + 5

x = 8, x = - 4

Solution steps

x^{2} + x - 27 = 5 x + 5

Move

5

to the left side

x^{2} + x - 32 = 5 x

Move

5 x

to the left side

x^{2} - 4 x - 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 32 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 32) = 12

x_{1, 2} = \frac{- ( - 4 ) \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 12}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 12}{2 \cdot 1}

x = \frac{- ( - 4 ) + 12}{2 \cdot 1} : 8

x = \frac{- ( - 4 ) - 12}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 8, x = - 4

x, 3 x^{2} + 5 y^{2} = 0

x^{2} + 2 x - 4 = - 4

3 x^{2} - 2 x = x - 1

x^{2} - 2 = 2 x - 2

x, 14 x^{2} + 36 x y - y^{2} - 3 x - 2 y = 0

What are the solutions to the equation x^2+x-27=5x+5 ?
The solutions to the equation x^2+x-27=5x+5 are x=8,x=-4
Find the zeros of x^2+x-27=5x+5
The zeros of x^2+x-27=5x+5 are x=8,x=-4