What are the solutions to the equation -4n^2-3n-6=0 ?

The solutions to the equation -4n^2-3n-6=0 are n=-3/8-i(sqrt(87))/8 ,n=-3/8+i(sqrt(87))/8

Find the zeros of -4n^2-3n-6=0

The zeros of -4n^2-3n-6=0 are n=-3/8-i(sqrt(87))/8 ,n=-3/8+i(sqrt(87))/8

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- 4 n^{2} - 3 n - 6 = 0

n = - \frac{3}{8} - i \frac{87}{8}, n = - \frac{3}{8} + i \frac{87}{8}

Solution steps

- 4 n^{2} - 3 n - 6 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 4 ) ( - 6 )}{2 ( - 4 )}

Simplify

(- 3)^{2} - 4 (- 4) (- 6) : 87 i

n_{1, 2} = \frac{- ( - 3 ) \pm 87 i}{2 ( - 4 )}

Separate the solutions

n_{1} = \frac{- ( - 3 ) + 87 i}{2 ( - 4 )}, n_{2} = \frac{- ( - 3 ) - 87 i}{2 ( - 4 )}

n = \frac{- ( - 3 ) + 87 i}{2 ( - 4 )} : - \frac{3}{8} - i \frac{87}{8}

n = \frac{- ( - 3 ) - 87 i}{2 ( - 4 )} : - \frac{3}{8} + i \frac{87}{8}

The solutions to the quadratic equation are:

n = - \frac{3}{8} - i \frac{87}{8}, n = - \frac{3}{8} + i \frac{87}{8}

x, 9 x^{2} - 5 x y + 7 y^{2} = 120

5 y^{2} - 30 y = 0

x, f^{- 1} (x) = x^{2}

x^{2} + 2.4 x + A = 0

4 x^{2} - 7 x + 83 = 0

What are the solutions to the equation -4n^2-3n-6=0 ?
The solutions to the equation -4n^2-3n-6=0 are n=-3/8-i(sqrt(87))/8 ,n=-3/8+i(sqrt(87))/8
Find the zeros of -4n^2-3n-6=0
The zeros of -4n^2-3n-6=0 are n=-3/8-i(sqrt(87))/8 ,n=-3/8+i(sqrt(87))/8