What are the solutions to the equation x^2+2.4x+A=0 ?

The solutions to the equation x^2+2.4x+A=0 are x=(-6+sqrt(-25A+36))/5 ,x=-(sqrt(-25A+36)+6)/5

Find the zeros of x^2+2.4x+A=0

The zeros of x^2+2.4x+A=0 are x=(-6+sqrt(-25A+36))/5 ,x=-(sqrt(-25A+36)+6)/5

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x^{2} + 2.4 x + A = 0

x = \frac{- 6 + - 25 A + 36}{5}, x = - \frac{- 25 A + 36 + 6}{5}

Solution steps

x^{2} + 2.4 x + A = 0

Multiply both sides by

10

10 x^{2} + 24 x + 10 A = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 10 \cdot 10 A}{2 \cdot 10}

Simplify

2 4^{2} - 4 \cdot 10 \cdot 10 A : 4 36 - 25 A

x_{1, 2} = \frac{- 24 \pm 4 36 - 25 A}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 24 + 4 36 - 25 A}{2 \cdot 10}, x_{2} = \frac{- 24 - 4 36 - 25 A}{2 \cdot 10}

x = \frac{- 24 + 4 36 - 25 A}{2 \cdot 10} : \frac{- 6 + - 25 A + 36}{5}

x = \frac{- 24 - 4 36 - 25 A}{2 \cdot 10} : - \frac{- 25 A + 36 + 6}{5}

The solutions to the quadratic equation are:

x = \frac{- 6 + - 25 A + 36}{5}, x = - \frac{- 25 A + 36 + 6}{5}

4 x^{2} - 7 x + 83 = 0

2 x^{2} - 8 x + 1

x^{2} + 8 x - 4 = - 4

4 r^{2} - 5 r - 6 = 0

4 x^{2} - 27 x + 18 = 0

What are the solutions to the equation x^2+2.4x+A=0 ?
The solutions to the equation x^2+2.4x+A=0 are x=(-6+sqrt(-25A+36))/5 ,x=-(sqrt(-25A+36)+6)/5
Find the zeros of x^2+2.4x+A=0
The zeros of x^2+2.4x+A=0 are x=(-6+sqrt(-25A+36))/5 ,x=-(sqrt(-25A+36)+6)/5