What are the solutions to the equation x^2-12x-5=-6x+2 ?

The solutions to the equation x^2-12x-5=-6x+2 are x=7,x=-1

Find the zeros of x^2-12x-5=-6x+2

The zeros of x^2-12x-5=-6x+2 are x=7,x=-1

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x^{2} - 12 x - 5 = - 6 x + 2

x = 7, x = - 1

Solution steps

x^{2} - 12 x - 5 = - 6 x + 2

Move

2

to the left side

x^{2} - 12 x - 7 = - 6 x

Move

6 x

to the left side

x^{2} - 6 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 7) = 8

x_{1, 2} = \frac{- ( - 6 ) \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 8}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 8}{2 \cdot 1}

x = \frac{- ( - 6 ) + 8}{2 \cdot 1} : 7

x = \frac{- ( - 6 ) - 8}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 7, x = - 1

9 p^{2} - 27 p + 20 = 0

x, x^{2} y^{2} - x - 4 y^{2} = 0

x^{2} - 2 x - 5 = - 5

x^{2} + 6 x - 49 = 6 x

x, 3 x^{2} + 2 x y - 3 y^{2} - 8 y - 2 = 0

What are the solutions to the equation x^2-12x-5=-6x+2 ?
The solutions to the equation x^2-12x-5=-6x+2 are x=7,x=-1
Find the zeros of x^2-12x-5=-6x+2
The zeros of x^2-12x-5=-6x+2 are x=7,x=-1