What are the solutions to the equation x^2+5x-3=-4x-3 ?

The solutions to the equation x^2+5x-3=-4x-3 are x=0,x=-9

Find the zeros of x^2+5x-3=-4x-3

The zeros of x^2+5x-3=-4x-3 are x=0,x=-9

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x^{2} + 5 x - 3 = - 4 x - 3

x = 0, x = - 9

Solution steps

x^{2} + 5 x - 3 = - 4 x - 3

Move

3

to the left side

x^{2} + 5 x = - 4 x

Move

4 x

to the left side

x^{2} + 9 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 0 = 9

x_{1, 2} = \frac{- 9 \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 9}{2 \cdot 1}, x_{2} = \frac{- 9 - 9}{2 \cdot 1}

x = \frac{- 9 + 9}{2 \cdot 1} : 0

x = \frac{- 9 - 9}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 0, x = - 9

x^{2} - 8 x + 48 = 0

x^{2} - 14 = - 5

(x + 13)^{2} = (x + 12)^{2} + (x - 5)^{2}

4 (a^{2} - 3) = 6 a + 4 (a + 3)

x, 9 x^{2} + 4 y^{2} - 36 x - 8 y + 76 = 0

What are the solutions to the equation x^2+5x-3=-4x-3 ?
The solutions to the equation x^2+5x-3=-4x-3 are x=0,x=-9
Find the zeros of x^2+5x-3=-4x-3
The zeros of x^2+5x-3=-4x-3 are x=0,x=-9