What are the solutions to the equation -3t^2+10t+5=-8t^2 ?

The solutions to the equation -3t^2+10t+5=-8t^2 are t=-1

Find the zeros of -3t^2+10t+5=-8t^2

The zeros of -3t^2+10t+5=-8t^2 are t=-1

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- 3 t^{2} + 10 t + 5 = - 8 t^{2}

t = - 1

Solution steps

- 3 t^{2} + 10 t + 5 = - 8 t^{2}

Move

8 t^{2}

to the left side

5 t^{2} + 10 t + 5 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 5 \cdot 5}{2 \cdot 5}

1 0^{2} - 4 \cdot 5 \cdot 5 = 0

t_{1, 2} = \frac{- 10 \pm 0}{2 \cdot 5}

t = \frac{- 10}{2 \cdot 5}

\frac{- 10}{2 \cdot 5} = - 1

t = - 1

The solution to the quadratic equation is:

t = - 1

x^{2} = 67 x

x^{2} - 8 x + 8 = - 4

2 x^{2} - 15 x + 2 = 0

8 (5 - 3 b)^{2} + 14 (5 - 3 b) = 15

x^{2} + x - 22 = x + 3

What are the solutions to the equation -3t^2+10t+5=-8t^2 ?
The solutions to the equation -3t^2+10t+5=-8t^2 are t=-1
Find the zeros of -3t^2+10t+5=-8t^2
The zeros of -3t^2+10t+5=-8t^2 are t=-1