What are the solutions to the equation -4k^2+5k=-3k-4 ?

The solutions to the equation -4k^2+5k=-3k-4 are k=1-sqrt(2),k=1+sqrt(2)

Find the zeros of -4k^2+5k=-3k-4

The zeros of -4k^2+5k=-3k-4 are k=1-sqrt(2),k=1+sqrt(2)

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- 4 k^{2} + 5 k = - 3 k - 4

k = 1 - 2, k = 1 + 2

Decimal Notation

k = - 0.41421 \dots, k = 2.41421 \dots

Solution steps

- 4 k^{2} + 5 k = - 3 k - 4

Move

4

to the left side

- 4 k^{2} + 5 k + 4 = - 3 k

Move

3 k

to the left side

- 4 k^{2} + 8 k + 4 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 4 ) \cdot 4}{2 ( - 4 )}

8^{2} - 4 (- 4) \cdot 4 = 82

k_{1, 2} = \frac{- 8 \pm 8 2}{2 ( - 4 )}

Separate the solutions

k_{1} = \frac{- 8 + 8 2}{2 ( - 4 )}, k_{2} = \frac{- 8 - 8 2}{2 ( - 4 )}

k = \frac{- 8 + 8 2}{2 ( - 4 )} : 1 - 2

k = \frac{- 8 - 8 2}{2 ( - 4 )} : 1 + 2

The solutions to the quadratic equation are:

k = 1 - 2, k = 1 + 2

\frac{4}{3} (x + 1)^{2} + 16 = 0

2 \cdot x^{2} - x - 2 = 0

x^{2} - 11 x - 46 = - 6 x + 4

x, x^{2} y - x^{2} + x y + 3 x - 2 = 0

6 x^{2} + x + 12 = 0

What are the solutions to the equation -4k^2+5k=-3k-4 ?
The solutions to the equation -4k^2+5k=-3k-4 are k=1-sqrt(2),k=1+sqrt(2)
Find the zeros of -4k^2+5k=-3k-4
The zeros of -4k^2+5k=-3k-4 are k=1-sqrt(2),k=1+sqrt(2)