What are the solutions to the equation (x+5)(x-1)=16 ?

The solutions to the equation (x+5)(x-1)=16 are x=3,x=-7

Find the zeros of (x+5)(x-1)=16

The zeros of (x+5)(x-1)=16 are x=3,x=-7

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(x + 5) (x - 1) = 16

x = 3, x = - 7

Solution steps

(x + 5) (x - 1) = 16

Expand

(x + 5) (x - 1) : x^{2} + 4 x - 5

x^{2} + 4 x - 5 = 16

Move

16

to the left side

x^{2} + 4 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 21 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 21) = 10

x_{1, 2} = \frac{- 4 \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 10}{2 \cdot 1}, x_{2} = \frac{- 4 - 10}{2 \cdot 1}

x = \frac{- 4 + 10}{2 \cdot 1} : 3

x = \frac{- 4 - 10}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 3, x = - 7

a, (a - 1)^{2} + (b - 2)^{2} = 0

2 x^{2} - 4 x - 4 = 2 x + 3

- r^{2} - 25 r + 20 = 0

x, f = 3 x y^{2} - 2 y + 5 x^{2} y^{2}

x^{2} - 16 x + 53 = - x - 3

What are the solutions to the equation (x+5)(x-1)=16 ?
The solutions to the equation (x+5)(x-1)=16 are x=3,x=-7
Find the zeros of (x+5)(x-1)=16
The zeros of (x+5)(x-1)=16 are x=3,x=-7