What are the solutions to the equation -r^2-25r+20=0 ?

The solutions to the equation -r^2-25r+20=0 are r=-(25+sqrt(705))/2 ,r=(sqrt(705)-25)/2

Find the zeros of -r^2-25r+20=0

The zeros of -r^2-25r+20=0 are r=-(25+sqrt(705))/2 ,r=(sqrt(705)-25)/2

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- r^{2} - 25 r + 20 = 0

r = - \frac{25 + 705}{2}, r = \frac{705 - 25}{2}

Decimal Notation

r = - 25.77591 \dots, r = 0.77591 \dots

Solution steps

- r^{2} - 25 r + 20 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 25 ) \pm ( - 25 ) ^{2} - 4 ( - 1 ) \cdot 20}{2 ( - 1 )}

(- 25)^{2} - 4 (- 1) \cdot 20 = 705

r_{1, 2} = \frac{- ( - 25 ) \pm 705}{2 ( - 1 )}

Separate the solutions

r_{1} = \frac{- ( - 25 ) + 705}{2 ( - 1 )}, r_{2} = \frac{- ( - 25 ) - 705}{2 ( - 1 )}

r = \frac{- ( - 25 ) + 705}{2 ( - 1 )} : - \frac{25 + 705}{2}

r = \frac{- ( - 25 ) - 705}{2 ( - 1 )} : \frac{705 - 25}{2}

The solutions to the quadratic equation are:

r = - \frac{25 + 705}{2}, r = \frac{705 - 25}{2}

x, f = 3 x y^{2} - 2 y + 5 x^{2} y^{2}

x^{2} - 16 x + 53 = - x - 3

48 - 2 x - x^{2} = 0

a x^{2} - x - a^{2} x + a = 0

x^{2} - 5 x - 1 = - 1

What are the solutions to the equation -r^2-25r+20=0 ?
The solutions to the equation -r^2-25r+20=0 are r=-(25+sqrt(705))/2 ,r=(sqrt(705)-25)/2
Find the zeros of -r^2-25r+20=0
The zeros of -r^2-25r+20=0 are r=-(25+sqrt(705))/2 ,r=(sqrt(705)-25)/2