What are the solutions to the equation 48-2x-x^2=0 ?

The solutions to the equation 48-2x-x^2=0 are x=-8,x=6

Find the zeros of 48-2x-x^2=0

The zeros of 48-2x-x^2=0 are x=-8,x=6

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48 - 2 x - x^{2} = 0

x = - 8, x = 6

Solution steps

48 - 2 x - x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} - 2 x + 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 1 ) \cdot 48}{2 ( - 1 )}

(- 2)^{2} - 4 (- 1) \cdot 48 = 14

x_{1, 2} = \frac{- ( - 2 ) \pm 14}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 14}{2 ( - 1 )}, x_{2} = \frac{- ( - 2 ) - 14}{2 ( - 1 )}

x = \frac{- ( - 2 ) + 14}{2 ( - 1 )} : - 8

x = \frac{- ( - 2 ) - 14}{2 ( - 1 )} : 6

The solutions to the quadratic equation are:

x = - 8, x = 6

a x^{2} - x - a^{2} x + a = 0

x^{2} - 5 x - 1 = - 1

M = (x + 1)^{2} + (x - 1)^{2} - 2

x, y = 4 - \frac{( x - 2 ) ^{2}}{4}

x, 4 x^{2} + 36 y^{2} + 9 z^{2} - 1 = 0

What are the solutions to the equation 48-2x-x^2=0 ?
The solutions to the equation 48-2x-x^2=0 are x=-8,x=6
Find the zeros of 48-2x-x^2=0
The zeros of 48-2x-x^2=0 are x=-8,x=6