What are the solutions to the equation 8y^2-26y+15=0 ?

The solutions to the equation 8y^2-26y+15=0 are y= 5/2 ,y= 3/4

Find the zeros of 8y^2-26y+15=0

The zeros of 8y^2-26y+15=0 are y= 5/2 ,y= 3/4

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8 y^{2} - 26 y + 15 = 0

y = \frac{5}{2}, y = \frac{3}{4}

Decimal Notation

y = 2.5, y = 0.75

Solution steps

8 y^{2} - 26 y + 15 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 26 ) \pm ( - 26 ) ^{2} - 4 \cdot 8 \cdot 15}{2 \cdot 8}

(- 26)^{2} - 4 \cdot 8 \cdot 15 = 14

y_{1, 2} = \frac{- ( - 26 ) \pm 14}{2 \cdot 8}

Separate the solutions

y_{1} = \frac{- ( - 26 ) + 14}{2 \cdot 8}, y_{2} = \frac{- ( - 26 ) - 14}{2 \cdot 8}

y = \frac{- ( - 26 ) + 14}{2 \cdot 8} : \frac{5}{2}

y = \frac{- ( - 26 ) - 14}{2 \cdot 8} : \frac{3}{4}

The solutions to the quadratic equation are:

y = \frac{5}{2}, y = \frac{3}{4}

2 x = 15 - x^{2}

x, (5 x + 4 y) (5 x - 4 y) = m x^{2} - n y^{2}

31 x^{2} - 40 x + 16 = 6 x^{2}

2 x^{2} - 7 x + 9 = x + 1

- 2 v^{2} + 13 v - 12 = - 6 v^{2}

What are the solutions to the equation 8y^2-26y+15=0 ?
The solutions to the equation 8y^2-26y+15=0 are y= 5/2 ,y= 3/4
Find the zeros of 8y^2-26y+15=0
The zeros of 8y^2-26y+15=0 are y= 5/2 ,y= 3/4