What are the solutions to the equation 31x^2-40x+16=6x^2 ?

The solutions to the equation 31x^2-40x+16=6x^2 are x= 4/5

Find the zeros of 31x^2-40x+16=6x^2

The zeros of 31x^2-40x+16=6x^2 are x= 4/5

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31 x^{2} - 40 x + 16 = 6 x^{2}

x = \frac{4}{5}

Decimal Notation

x = 0.8

Solution steps

31 x^{2} - 40 x + 16 = 6 x^{2}

Move

6 x^{2}

to the left side

25 x^{2} - 40 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 25 \cdot 16}{2 \cdot 25}

(- 40)^{2} - 4 \cdot 25 \cdot 16 = 0

x_{1, 2} = \frac{- ( - 40 ) \pm 0}{2 \cdot 25}

x = \frac{- ( - 40 )}{2 \cdot 25}

\frac{- ( - 40 )}{2 \cdot 25} = \frac{4}{5}

x = \frac{4}{5}

The solution to the quadratic equation is:

x = \frac{4}{5}

2 x^{2} - 7 x + 9 = x + 1

- 2 v^{2} + 13 v - 12 = - 6 v^{2}

x^{2} - 4 x = - 5 x

5 x^{2} = 19 x

7 w^{2} + 2 w - 3 = - w^{2}

What are the solutions to the equation 31x^2-40x+16=6x^2 ?
The solutions to the equation 31x^2-40x+16=6x^2 are x= 4/5
Find the zeros of 31x^2-40x+16=6x^2
The zeros of 31x^2-40x+16=6x^2 are x= 4/5