What are the solutions to the equation 7w^2+2w-3=-w^2 ?

The solutions to the equation 7w^2+2w-3=-w^2 are w= 1/2 ,w=-3/4

Find the zeros of 7w^2+2w-3=-w^2

The zeros of 7w^2+2w-3=-w^2 are w= 1/2 ,w=-3/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

7 w^{2} + 2 w - 3 = - w^{2}

w = \frac{1}{2}, w = - \frac{3}{4}

Decimal Notation

w = 0.5, w = - 0.75

Solution steps

7 w^{2} + 2 w - 3 = - w^{2}

Move

w^{2}

to the left side

8 w^{2} + 2 w - 3 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 8 ( - 3 )}{2 \cdot 8}

2^{2} - 4 \cdot 8 (- 3) = 10

w_{1, 2} = \frac{- 2 \pm 10}{2 \cdot 8}

Separate the solutions

w_{1} = \frac{- 2 + 10}{2 \cdot 8}, w_{2} = \frac{- 2 - 10}{2 \cdot 8}

w = \frac{- 2 + 10}{2 \cdot 8} : \frac{1}{2}

w = \frac{- 2 - 10}{2 \cdot 8} : - \frac{3}{4}

The solutions to the quadratic equation are:

w = \frac{1}{2}, w = - \frac{3}{4}

x^{2} - 33 = 3

25 q^{2} - 40 q + 16 = 0

\frac{1}{2} x^{2} - 9 = 0

x^{2} + 12 x + 13 = x + 3

x^{2} + 35 x + 65 = 0

What are the solutions to the equation 7w^2+2w-3=-w^2 ?
The solutions to the equation 7w^2+2w-3=-w^2 are w= 1/2 ,w=-3/4
Find the zeros of 7w^2+2w-3=-w^2
The zeros of 7w^2+2w-3=-w^2 are w= 1/2 ,w=-3/4