What are the solutions to the equation 25q^2-40q+16=0 ?

The solutions to the equation 25q^2-40q+16=0 are q= 4/5

Find the zeros of 25q^2-40q+16=0

The zeros of 25q^2-40q+16=0 are q= 4/5

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25 q^{2} - 40 q + 16 = 0

q = \frac{4}{5}

Decimal Notation

q = 0.8

Solution steps

25 q^{2} - 40 q + 16 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 25 \cdot 16}{2 \cdot 25}

(- 40)^{2} - 4 \cdot 25 \cdot 16 = 0

q_{1, 2} = \frac{- ( - 40 ) \pm 0}{2 \cdot 25}

q = \frac{- ( - 40 )}{2 \cdot 25}

\frac{- ( - 40 )}{2 \cdot 25} = \frac{4}{5}

q = \frac{4}{5}

The solution to the quadratic equation is:

q = \frac{4}{5}

\frac{1}{2} x^{2} - 9 = 0

x^{2} + 12 x + 13 = x + 3

x^{2} + 35 x + 65 = 0

(2 n - 8) x^{2} + 9 x = 18

3 x^{2} + 24 x - 24 = 0

What are the solutions to the equation 25q^2-40q+16=0 ?
The solutions to the equation 25q^2-40q+16=0 are q= 4/5
Find the zeros of 25q^2-40q+16=0
The zeros of 25q^2-40q+16=0 are q= 4/5