What are the solutions to the equation 3x^2+24x-24=0 ?

The solutions to the equation 3x^2+24x-24=0 are x=2(sqrt(6)-2),x=-2(2+sqrt(6))

Find the zeros of 3x^2+24x-24=0

The zeros of 3x^2+24x-24=0 are x=2(sqrt(6)-2),x=-2(2+sqrt(6))

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3 x^{2} + 24 x - 24 = 0

x = 2 (6 - 2), x = - 2 (2 + 6)

Decimal Notation

x = 0.89897 \dots, x = - 8.89897 \dots

Solution steps

3 x^{2} + 24 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 3 ( - 24 )}{2 \cdot 3}

2 4^{2} - 4 \cdot 3 (- 24) = 126

x_{1, 2} = \frac{- 24 \pm 12 6}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 24 + 12 6}{2 \cdot 3}, x_{2} = \frac{- 24 - 12 6}{2 \cdot 3}

x = \frac{- 24 + 12 6}{2 \cdot 3} : 2 (6 - 2)

x = \frac{- 24 - 12 6}{2 \cdot 3} : - 2 (2 + 6)

The solutions to the quadratic equation are:

x = 2 (6 - 2), x = - 2 (2 + 6)

x, 4 x^{2} + 4 y^{2} + z^{2} = 16

[- x - 3]^{2} = 5 - 2 [- x]

4 + x (x - 4) = x

x, 2 x^{2} + 3 y^{2} - x + 3 y + 6 = 0

(x - 1)^{2} - 4 = 44

What are the solutions to the equation 3x^2+24x-24=0 ?
The solutions to the equation 3x^2+24x-24=0 are x=2(sqrt(6)-2),x=-2(2+sqrt(6))
Find the zeros of 3x^2+24x-24=0
The zeros of 3x^2+24x-24=0 are x=2(sqrt(6)-2),x=-2(2+sqrt(6))