What are the solutions to the equation 4+x(x-4)=x ?

The solutions to the equation 4+x(x-4)=x are x=4,x=1

Find the zeros of 4+x(x-4)=x

The zeros of 4+x(x-4)=x are x=4,x=1

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4 + x (x - 4) = x

x = 4, x = 1

Solution steps

4 + x (x - 4) = x

Expand

4 + x (x - 4) : 4 + x^{2} - 4 x

4 + x^{2} - 4 x = x

Move

x

to the left side

4 + x^{2} - 5 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 5 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 4 = 3

x_{1, 2} = \frac{- ( - 5 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 3}{2 \cdot 1}

x = \frac{- ( - 5 ) + 3}{2 \cdot 1} : 4

x = \frac{- ( - 5 ) - 3}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 4, x = 1

x, 2 x^{2} + 3 y^{2} - x + 3 y + 6 = 0

(x - 1)^{2} - 4 = 44

2 x^{2} - 19 x + 45 = 0

- 3 y^{2} - 4 y

3 p (p + 3) = p - 3

What are the solutions to the equation 4+x(x-4)=x ?
The solutions to the equation 4+x(x-4)=x are x=4,x=1
Find the zeros of 4+x(x-4)=x
The zeros of 4+x(x-4)=x are x=4,x=1