What are the solutions to the equation (2x+2)^2=-33 ?

The solutions to the equation (2x+2)^2=-33 are x=-1+i(sqrt(33))/2 ,x=-1-i(sqrt(33))/2

Find the zeros of (2x+2)^2=-33

The zeros of (2x+2)^2=-33 are x=-1+i(sqrt(33))/2 ,x=-1-i(sqrt(33))/2

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(2 x + 2)^{2} = - 33

x = - 1 + i \frac{33}{2}, x = - 1 - i \frac{33}{2}

Solution steps

(2 x + 2)^{2} = - 33

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 2 = - 33 : x = - 1 + i \frac{33}{2}

Solve

2 x + 2 = - - 33 : x = - 1 - i \frac{33}{2}

The solutions to the quadratic equation are:

x = - 1 + i \frac{33}{2}, x = - 1 - i \frac{33}{2}

8 y^{2} - 10 y - 42 = 0

x, z = x^{2} + y^{2} + 1

12 x^{2} - 22 x - 5 = - 5 x

3 x^{2} + 4 x + 2 = - x

x^{2} = 0.04 4^{2} + 0.05 6^{2}

What are the solutions to the equation (2x+2)^2=-33 ?
The solutions to the equation (2x+2)^2=-33 are x=-1+i(sqrt(33))/2 ,x=-1-i(sqrt(33))/2
Find the zeros of (2x+2)^2=-33
The zeros of (2x+2)^2=-33 are x=-1+i(sqrt(33))/2 ,x=-1-i(sqrt(33))/2