What are the solutions to the equation x^2=0.044^2+0.056^2 ?

The solutions to the equation x^2=0.044^2+0.056^2 are x=(sqrt(317))/(250),x=-(sqrt(317))/(250)

Find the zeros of x^2=0.044^2+0.056^2

The zeros of x^2=0.044^2+0.056^2 are x=(sqrt(317))/(250),x=-(sqrt(317))/(250)

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x^{2} = 0.04 4^{2} + 0.05 6^{2}

x = \frac{317}{250}, x = - \frac{317}{250}

Decimal Notation

x = 0.07121 \dots, x = - 0.07121 \dots

Solution steps

x^{2} = 0.04 4^{2} + 0.05 6^{2}

Simplify

0.04 4^{2} + 0.05 6^{2} : 0.005072

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 0.005072, x = - 0.005072

0.005072 = \frac{317}{250}

- 0.005072 = - \frac{317}{250}

x = \frac{317}{250}, x = - \frac{317}{250}

3 x - 4 x^{2} = 0

(3 x + 1)^{2} - (x - 1) (x + 5) = (3 x + 5) (3 x - 5)

2 v^{2} + 13 v + 17 = 0

x^{2} - 13 x = - 7 x + 40

4 x^{2} - 780 x + 2304 = 0

What are the solutions to the equation x^2=0.044^2+0.056^2 ?
The solutions to the equation x^2=0.044^2+0.056^2 are x=(sqrt(317))/(250),x=-(sqrt(317))/(250)
Find the zeros of x^2=0.044^2+0.056^2
The zeros of x^2=0.044^2+0.056^2 are x=(sqrt(317))/(250),x=-(sqrt(317))/(250)