What are the solutions to the equation 2q^2-3q-15=-4q ?

The solutions to the equation 2q^2-3q-15=-4q are q= 5/2 ,q=-3

Find the zeros of 2q^2-3q-15=-4q

The zeros of 2q^2-3q-15=-4q are q= 5/2 ,q=-3

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2 q^{2} - 3 q - 15 = - 4 q

q = \frac{5}{2}, q = - 3

Decimal Notation

q = 2.5, q = - 3

Solution steps

2 q^{2} - 3 q - 15 = - 4 q

Move

4 q

to the left side

2 q^{2} + q - 15 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 ( - 15 )}{2 \cdot 2}

1^{2} - 4 \cdot 2 (- 15) = 11

q_{1, 2} = \frac{- 1 \pm 11}{2 \cdot 2}

Separate the solutions

q_{1} = \frac{- 1 + 11}{2 \cdot 2}, q_{2} = \frac{- 1 - 11}{2 \cdot 2}

q = \frac{- 1 + 11}{2 \cdot 2} : \frac{5}{2}

q = \frac{- 1 - 11}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

q = \frac{5}{2}, q = - 3

11 d^{2} - 12 d + 4 = 6 d^{2}

- x^{2} = 8 x - 2

1200 - 1.5 q^{2} = 200 + q^{2}

9 q^{2} + 30 q + 25 = 0

1 + 4 x - x^{2}

What are the solutions to the equation 2q^2-3q-15=-4q ?
The solutions to the equation 2q^2-3q-15=-4q are q= 5/2 ,q=-3
Find the zeros of 2q^2-3q-15=-4q
The zeros of 2q^2-3q-15=-4q are q= 5/2 ,q=-3