What are the solutions to the equation 1200-1.5q^2=200+q^2 ?

The solutions to the equation 1200-1.5q^2=200+q^2 are q=20,q=-20

Find the zeros of 1200-1.5q^2=200+q^2

The zeros of 1200-1.5q^2=200+q^2 are q=20,q=-20

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1200 - 1.5 q^{2} = 200 + q^{2}

q = 20, q = - 20

Solution steps

1200 - 1.5 q^{2} = 200 + q^{2}

Move

1200

to the right side

- 1.5 q^{2} = q^{2} - 1000

Move

q^{2}

to the left side

- 2.5 q^{2} = - 1000

Divide both sides by

- 2.5

q^{2} = 400

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

q = 400, q = - 400

400 = 20

- 400 = - 20

q = 20, q = - 20

9 q^{2} + 30 q + 25 = 0

1 + 4 x - x^{2}

x^{2} + 7 x + 3 = 3

(2 x + 3)^{2} = 2 (6 x + 4)

\frac{1}{3} x^{2} - \frac{7}{3} x = - 4

What are the solutions to the equation 1200-1.5q^2=200+q^2 ?
The solutions to the equation 1200-1.5q^2=200+q^2 are q=20,q=-20
Find the zeros of 1200-1.5q^2=200+q^2
The zeros of 1200-1.5q^2=200+q^2 are q=20,q=-20