What are the solutions to the equation 1/3 x^2-7/3 x=-4 ?

The solutions to the equation 1/3 x^2-7/3 x=-4 are x=4,x=3

Find the zeros of 1/3 x^2-7/3 x=-4

The zeros of 1/3 x^2-7/3 x=-4 are x=4,x=3

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\frac{1}{3} x^{2} - \frac{7}{3} x = - 4

x = 4, x = 3

Solution steps

\frac{1}{3} x^{2} - \frac{7}{3} x = - 4

Multiply both sides by

3

x^{2} - 7 x = - 12

Move

12

to the left side

x^{2} - 7 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 12 = 1

x_{1, 2} = \frac{- ( - 7 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 1}{2 \cdot 1}

x = \frac{- ( - 7 ) + 1}{2 \cdot 1} : 4

x = \frac{- ( - 7 ) - 1}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

x = 4, x = 3

A (x) = \frac{x ^{2}}{16} + 144 x^{2}

5 a^{2} + 15 a + 7 = 0

(2 m - 1) x^{2} + (5 m + 1) x - 3 = 0

x^{2} + (\frac{9}{8})^{2} = 1

a, a^{2} + ab - 2 a - 2 b = 0

What are the solutions to the equation 1/3 x^2-7/3 x=-4 ?
The solutions to the equation 1/3 x^2-7/3 x=-4 are x=4,x=3
Find the zeros of 1/3 x^2-7/3 x=-4
The zeros of 1/3 x^2-7/3 x=-4 are x=4,x=3