What are the solutions to the equation x^2-9x-9=-5x-4 ?

The solutions to the equation x^2-9x-9=-5x-4 are x=5,x=-1

Find the zeros of x^2-9x-9=-5x-4

The zeros of x^2-9x-9=-5x-4 are x=5,x=-1

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x^{2} - 9 x - 9 = - 5 x - 4

x = 5, x = - 1

Solution steps

x^{2} - 9 x - 9 = - 5 x - 4

Move

4

to the left side

x^{2} - 9 x - 5 = - 5 x

Move

5 x

to the left side

x^{2} - 4 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 5) = 6

x_{1, 2} = \frac{- ( - 4 ) \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 6}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 6}{2 \cdot 1}

x = \frac{- ( - 4 ) + 6}{2 \cdot 1} : 5

x = \frac{- ( - 4 ) - 6}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 5, x = - 1

8 c^{2} + 18 c - 7 = - 2

x, 9 x^{2} + 16 y^{2} + 36 x - 100 y = - 292

x^{2} + x - 16 = x

ab (x^{2} - c^{2}) = (a^{2} - b^{2}) c x

x^{2} + x - 22 = 8

What are the solutions to the equation x^2-9x-9=-5x-4 ?
The solutions to the equation x^2-9x-9=-5x-4 are x=5,x=-1
Find the zeros of x^2-9x-9=-5x-4
The zeros of x^2-9x-9=-5x-4 are x=5,x=-1