What are the solutions to the equation 8c^2+18c-7=-2 ?

The solutions to the equation 8c^2+18c-7=-2 are c= 1/4 ,c=-5/2

Find the zeros of 8c^2+18c-7=-2

The zeros of 8c^2+18c-7=-2 are c= 1/4 ,c=-5/2

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8 c^{2} + 18 c - 7 = - 2

c = \frac{1}{4}, c = - \frac{5}{2}

Decimal Notation

c = 0.25, c = - 2.5

Solution steps

8 c^{2} + 18 c - 7 = - 2

Move

2

to the left side

8 c^{2} + 18 c - 5 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 8 ( - 5 )}{2 \cdot 8}

1 8^{2} - 4 \cdot 8 (- 5) = 22

c_{1, 2} = \frac{- 18 \pm 22}{2 \cdot 8}

Separate the solutions

c_{1} = \frac{- 18 + 22}{2 \cdot 8}, c_{2} = \frac{- 18 - 22}{2 \cdot 8}

c = \frac{- 18 + 22}{2 \cdot 8} : \frac{1}{4}

c = \frac{- 18 - 22}{2 \cdot 8} : - \frac{5}{2}

The solutions to the quadratic equation are:

c = \frac{1}{4}, c = - \frac{5}{2}

x, 9 x^{2} + 16 y^{2} + 36 x - 100 y = - 292

x^{2} + x - 16 = x

ab (x^{2} - c^{2}) = (a^{2} - b^{2}) c x

x^{2} + x - 22 = 8

4 d^{2} + 9 d - 7 = 2

What are the solutions to the equation 8c^2+18c-7=-2 ?
The solutions to the equation 8c^2+18c-7=-2 are c= 1/4 ,c=-5/2
Find the zeros of 8c^2+18c-7=-2
The zeros of 8c^2+18c-7=-2 are c= 1/4 ,c=-5/2