What are the solutions to the equation 4d^2+9d-7=2 ?

The solutions to the equation 4d^2+9d-7=2 are d= 3/4 ,d=-3

Find the zeros of 4d^2+9d-7=2

The zeros of 4d^2+9d-7=2 are d= 3/4 ,d=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 d^{2} + 9 d - 7 = 2

d = \frac{3}{4}, d = - 3

Decimal Notation

d = 0.75, d = - 3

Solution steps

4 d^{2} + 9 d - 7 = 2

Move

2

to the left side

4 d^{2} + 9 d - 9 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 4 ( - 9 )}{2 \cdot 4}

9^{2} - 4 \cdot 4 (- 9) = 15

d_{1, 2} = \frac{- 9 \pm 15}{2 \cdot 4}

Separate the solutions

d_{1} = \frac{- 9 + 15}{2 \cdot 4}, d_{2} = \frac{- 9 - 15}{2 \cdot 4}

d = \frac{- 9 + 15}{2 \cdot 4} : \frac{3}{4}

d = \frac{- 9 - 15}{2 \cdot 4} : - 3

The solutions to the quadratic equation are:

d = \frac{3}{4}, d = - 3

x^{2} - 160 x + 10000 = 0

y^{2} - 2 y - 3 = y - 3

x^{2} - 6 x = 2 x

x^{2} - 9 x + 3 = 3

6 x^{2} - 23 x = 20

What are the solutions to the equation 4d^2+9d-7=2 ?
The solutions to the equation 4d^2+9d-7=2 are d= 3/4 ,d=-3
Find the zeros of 4d^2+9d-7=2
The zeros of 4d^2+9d-7=2 are d= 3/4 ,d=-3