What are the solutions to the equation 12r^2-9r-25=-4r ?

The solutions to the equation 12r^2-9r-25=-4r are r= 5/3 ,r=-5/4

Find the zeros of 12r^2-9r-25=-4r

The zeros of 12r^2-9r-25=-4r are r= 5/3 ,r=-5/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

12 r^{2} - 9 r - 25 = - 4 r

r = \frac{5}{3}, r = - \frac{5}{4}

Decimal Notation

r = 1.66666 \dots, r = - 1.25

Solution steps

12 r^{2} - 9 r - 25 = - 4 r

Move

4 r

to the left side

12 r^{2} - 5 r - 25 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 12 ( - 25 )}{2 \cdot 12}

(- 5)^{2} - 4 \cdot 12 (- 25) = 35

r_{1, 2} = \frac{- ( - 5 ) \pm 35}{2 \cdot 12}

Separate the solutions

r_{1} = \frac{- ( - 5 ) + 35}{2 \cdot 12}, r_{2} = \frac{- ( - 5 ) - 35}{2 \cdot 12}

r = \frac{- ( - 5 ) + 35}{2 \cdot 12} : \frac{5}{3}

r = \frac{- ( - 5 ) - 35}{2 \cdot 12} : - \frac{5}{4}

The solutions to the quadratic equation are:

r = \frac{5}{3}, r = - \frac{5}{4}

5 m^{2} + 13 m + 12 = 6

2 x^{2} + 5 = 27

x^{2} + 8 x + 9 = 16 x + 29

x, z = 1 - 2 y^{2} - 3 x^{2}

4 x^{2} + 10 x + 4 = 3 x + 6

What are the solutions to the equation 12r^2-9r-25=-4r ?
The solutions to the equation 12r^2-9r-25=-4r are r= 5/3 ,r=-5/4
Find the zeros of 12r^2-9r-25=-4r
The zeros of 12r^2-9r-25=-4r are r= 5/3 ,r=-5/4