What are the solutions to the equation x^2+8x+9=16x+29 ?

The solutions to the equation x^2+8x+9=16x+29 are x=10,x=-2

Find the zeros of x^2+8x+9=16x+29

The zeros of x^2+8x+9=16x+29 are x=10,x=-2

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x^{2} + 8 x + 9 = 16 x + 29

x = 10, x = - 2

Solution steps

x^{2} + 8 x + 9 = 16 x + 29

Move

29

to the left side

x^{2} + 8 x - 20 = 16 x

Move

16 x

to the left side

x^{2} - 8 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 20) = 12

x_{1, 2} = \frac{- ( - 8 ) \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 12}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 12}{2 \cdot 1}

x = \frac{- ( - 8 ) + 12}{2 \cdot 1} : 10

x = \frac{- ( - 8 ) - 12}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 10, x = - 2

x, z = 1 - 2 y^{2} - 3 x^{2}

4 x^{2} + 10 x + 4 = 3 x + 6

36 x^{2} = 9 x

0.2 x^{2} + 2 x + 15 = 0

a, v = \frac{1}{3} a^{2} h

What are the solutions to the equation x^2+8x+9=16x+29 ?
The solutions to the equation x^2+8x+9=16x+29 are x=10,x=-2
Find the zeros of x^2+8x+9=16x+29
The zeros of x^2+8x+9=16x+29 are x=10,x=-2