What are the solutions to the equation x^2+12x=10 ?

The solutions to the equation x^2+12x=10 are x=-6+sqrt(46),x=-6-sqrt(46)

Find the zeros of x^2+12x=10

The zeros of x^2+12x=10 are x=-6+sqrt(46),x=-6-sqrt(46)

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x^{2} + 12 x = 10

x = - 6 + 46, x = - 6 - 46

Decimal Notation

x = 0.78232 \dots, x = - 12.78232 \dots

Solution steps

x^{2} + 12 x = 10

Move

10

to the left side

x^{2} + 12 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot (- 10) = 246

x_{1, 2} = \frac{- 12 \pm 2 46}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 2 46}{2 \cdot 1}, x_{2} = \frac{- 12 - 2 46}{2 \cdot 1}

x = \frac{- 12 + 2 46}{2 \cdot 1} : - 6 + 46

x = \frac{- 12 - 2 46}{2 \cdot 1} : - 6 - 46

The solutions to the quadratic equation are:

x = - 6 + 46, x = - 6 - 46

x^{2} - 15 x = - 8 x + 18

(x + 1)^{2} - 2 x = - 2 x

- 2 x^{2} + 60 x - 120 = 0

3 n^{2} + 17 n + 17 = - 2

x, 2 x^{2} + y^{2} - x + 3 y + 6 = 0

What are the solutions to the equation x^2+12x=10 ?
The solutions to the equation x^2+12x=10 are x=-6+sqrt(46),x=-6-sqrt(46)
Find the zeros of x^2+12x=10
The zeros of x^2+12x=10 are x=-6+sqrt(46),x=-6-sqrt(46)