What are the solutions to the equation 9v^2+12v+5=1 ?

The solutions to the equation 9v^2+12v+5=1 are v=-2/3

Find the zeros of 9v^2+12v+5=1

The zeros of 9v^2+12v+5=1 are v=-2/3

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9 v^{2} + 12 v + 5 = 1

v = - \frac{2}{3}

Decimal Notation

v = - 0.66666 \dots

Solution steps

9 v^{2} + 12 v + 5 = 1

Move

1

to the left side

9 v^{2} + 12 v + 4 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 9 \cdot 4}{2 \cdot 9}

1 2^{2} - 4 \cdot 9 \cdot 4 = 0

v_{1, 2} = \frac{- 12 \pm 0}{2 \cdot 9}

v = \frac{- 12}{2 \cdot 9}

\frac{- 12}{2 \cdot 9} = - \frac{2}{3}

v = - \frac{2}{3}

The solution to the quadratic equation is:

v = - \frac{2}{3}

x^{2} = 2 x - 3

- x^{2} + 30 x - 2 = 0

(4 - 3 x)^{2} = 64

x^{2} + 12 x + c = 0

12 = 3 x^{2} - 18 x

What are the solutions to the equation 9v^2+12v+5=1 ?
The solutions to the equation 9v^2+12v+5=1 are v=-2/3
Find the zeros of 9v^2+12v+5=1
The zeros of 9v^2+12v+5=1 are v=-2/3