What are the solutions to the equation 5(x-3)-x(x-3)=0 ?

The solutions to the equation 5(x-3)-x(x-3)=0 are x=3,x=5

Find the zeros of 5(x-3)-x(x-3)=0

The zeros of 5(x-3)-x(x-3)=0 are x=3,x=5

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5 (x - 3) - x (x - 3) = 0

x = 3, x = 5

Solution steps

5 (x - 3) - x (x - 3) = 0

Expand

5 (x - 3) - x (x - 3) : - x^{2} + 8 x - 15

- x^{2} + 8 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 1 ) ( - 15 )}{2 ( - 1 )}

8^{2} - 4 (- 1) (- 15) = 2

x_{1, 2} = \frac{- 8 \pm 2}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 8 + 2}{2 ( - 1 )}, x_{2} = \frac{- 8 - 2}{2 ( - 1 )}

x = \frac{- 8 + 2}{2 ( - 1 )} : 3

x = \frac{- 8 - 2}{2 ( - 1 )} : 5

The solutions to the quadratic equation are:

x = 3, x = 5

12 x^{2} = 4 x

5 q^{2} + 7 q - 1 = 0

10 x^{2} + 13 x = 3

x, x - 2 x y + x^{2} y + y = 10

x^{2} + 6 x - 64 = 6 x

What are the solutions to the equation 5(x-3)-x(x-3)=0 ?
The solutions to the equation 5(x-3)-x(x-3)=0 are x=3,x=5
Find the zeros of 5(x-3)-x(x-3)=0
The zeros of 5(x-3)-x(x-3)=0 are x=3,x=5