What are the solutions to the equation 5q^2+7q-1=0 ?

The solutions to the equation 5q^2+7q-1=0 are q=(-7+sqrt(69))/(10),q=(-7-sqrt(69))/(10)

Find the zeros of 5q^2+7q-1=0

The zeros of 5q^2+7q-1=0 are q=(-7+sqrt(69))/(10),q=(-7-sqrt(69))/(10)

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5 q^{2} + 7 q - 1 = 0

q = \frac{- 7 + 69}{10}, q = \frac{- 7 - 69}{10}

Decimal Notation

q = 0.13066 \dots, q = - 1.53066 \dots

Solution steps

5 q^{2} + 7 q - 1 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 5 ( - 1 )}{2 \cdot 5}

7^{2} - 4 \cdot 5 (- 1) = 69

q_{1, 2} = \frac{- 7 \pm 69}{2 \cdot 5}

Separate the solutions

q_{1} = \frac{- 7 + 69}{2 \cdot 5}, q_{2} = \frac{- 7 - 69}{2 \cdot 5}

q = \frac{- 7 + 69}{2 \cdot 5} : \frac{- 7 + 69}{10}

q = \frac{- 7 - 69}{2 \cdot 5} : \frac{- 7 - 69}{10}

The solutions to the quadratic equation are:

q = \frac{- 7 + 69}{10}, q = \frac{- 7 - 69}{10}

10 x^{2} + 13 x = 3

x, x - 2 x y + x^{2} y + y = 10

x^{2} + 6 x - 64 = 6 x

12 w^{2} + 21 w + 10 = 3 w^{2}

5 n^{2} - 20 n + 25 = n^{2}

What are the solutions to the equation 5q^2+7q-1=0 ?
The solutions to the equation 5q^2+7q-1=0 are q=(-7+sqrt(69))/(10),q=(-7-sqrt(69))/(10)
Find the zeros of 5q^2+7q-1=0
The zeros of 5q^2+7q-1=0 are q=(-7+sqrt(69))/(10),q=(-7-sqrt(69))/(10)