What are the solutions to the equation 12w^2+21w+10=3w^2 ?

The solutions to the equation 12w^2+21w+10=3w^2 are w=-2/3 ,w=-5/3

Find the zeros of 12w^2+21w+10=3w^2

The zeros of 12w^2+21w+10=3w^2 are w=-2/3 ,w=-5/3

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12 w^{2} + 21 w + 10 = 3 w^{2}

w = - \frac{2}{3}, w = - \frac{5}{3}

Decimal Notation

w = - 0.66666 \dots, w = - 1.66666 \dots

Solution steps

12 w^{2} + 21 w + 10 = 3 w^{2}

Move

3 w^{2}

to the left side

9 w^{2} + 21 w + 10 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 21 \pm 2 1 ^{2} - 4 \cdot 9 \cdot 10}{2 \cdot 9}

2 1^{2} - 4 \cdot 9 \cdot 10 = 9

w_{1, 2} = \frac{- 21 \pm 9}{2 \cdot 9}

Separate the solutions

w_{1} = \frac{- 21 + 9}{2 \cdot 9}, w_{2} = \frac{- 21 - 9}{2 \cdot 9}

w = \frac{- 21 + 9}{2 \cdot 9} : - \frac{2}{3}

w = \frac{- 21 - 9}{2 \cdot 9} : - \frac{5}{3}

The solutions to the quadratic equation are:

w = - \frac{2}{3}, w = - \frac{5}{3}

5 n^{2} - 20 n + 25 = n^{2}

12 x^{2} - 3 x + 2 = 0

2 c^{2} - 9 c + 5 = 2 c

6 n^{2} + 10 n + 25 = 5 n^{2}

4 y^{2} - 8 y - 10 = - 5

What are the solutions to the equation 12w^2+21w+10=3w^2 ?
The solutions to the equation 12w^2+21w+10=3w^2 are w=-2/3 ,w=-5/3
Find the zeros of 12w^2+21w+10=3w^2
The zeros of 12w^2+21w+10=3w^2 are w=-2/3 ,w=-5/3