What are the solutions to the equation 3x^2-6x=-4 ?

The solutions to the equation 3x^2-6x=-4 are x=1+i(sqrt(3))/3 ,x=1-i(sqrt(3))/3

Find the zeros of 3x^2-6x=-4

The zeros of 3x^2-6x=-4 are x=1+i(sqrt(3))/3 ,x=1-i(sqrt(3))/3

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3 x^{2} - 6 x = - 4

x = 1 + i \frac{3}{3}, x = 1 - i \frac{3}{3}

Solution steps

3 x^{2} - 6 x = - 4

Move

4

to the left side

3 x^{2} - 6 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 \cdot 4}{2 \cdot 3}

Simplify

(- 6)^{2} - 4 \cdot 3 \cdot 4 : 23 i

x_{1, 2} = \frac{- ( - 6 ) \pm 2 3 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 3 i}{2 \cdot 3}, x_{2} = \frac{- ( - 6 ) - 2 3 i}{2 \cdot 3}

x = \frac{- ( - 6 ) + 2 3 i}{2 \cdot 3} : 1 + i \frac{3}{3}

x = \frac{- ( - 6 ) - 2 3 i}{2 \cdot 3} : 1 - i \frac{3}{3}

The solutions to the quadratic equation are:

x = 1 + i \frac{3}{3}, x = 1 - i \frac{3}{3}

\frac{3 x + 2}{2 x - 7} < 0

a^{2} - 9 a + 14 = 0

(i)^{3}

(x - 3)^{2} + 19 = 20

2 \geq \frac{1}{3} (6 - x)

What are the solutions to the equation 3x^2-6x=-4 ?
The solutions to the equation 3x^2-6x=-4 are x=1+i(sqrt(3))/3 ,x=1-i(sqrt(3))/3
Find the zeros of 3x^2-6x=-4
The zeros of 3x^2-6x=-4 are x=1+i(sqrt(3))/3 ,x=1-i(sqrt(3))/3