What are the solutions to the equation a^2-9a+14=0 ?

The solutions to the equation a^2-9a+14=0 are a=7,a=2

Find the zeros of a^2-9a+14=0

The zeros of a^2-9a+14=0 are a=7,a=2

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a^{2} - 9 a + 14 = 0

a = 7, a = 2

Solution steps

a^{2} - 9 a + 14 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 14}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 14 = 5

a_{1, 2} = \frac{- ( - 9 ) \pm 5}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 9 ) + 5}{2 \cdot 1}, a_{2} = \frac{- ( - 9 ) - 5}{2 \cdot 1}

a = \frac{- ( - 9 ) + 5}{2 \cdot 1} : 7

a = \frac{- ( - 9 ) - 5}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

a = 7, a = 2

(i)^{3}

(x - 3)^{2} + 19 = 20

2 \geq \frac{1}{3} (6 - x)

- 3 x^{2} + 6 x + 3 = 0

x + 3 \leq - 6

What are the solutions to the equation a^2-9a+14=0 ?
The solutions to the equation a^2-9a+14=0 are a=7,a=2
Find the zeros of a^2-9a+14=0
The zeros of a^2-9a+14=0 are a=7,a=2