What are the solutions to the equation 3x^2+4x+9=8 ?

The solutions to the equation 3x^2+4x+9=8 are x=-1/3 ,x=-1

Find the zeros of 3x^2+4x+9=8

The zeros of 3x^2+4x+9=8 are x=-1/3 ,x=-1

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3 x^{2} + 4 x + 9 = 8

x = - \frac{1}{3}, x = - 1

Decimal Notation

x = - 0.33333 \dots, x = - 1

Solution steps

3 x^{2} + 4 x + 9 = 8

Move

8

to the left side

3 x^{2} + 4 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 3 \cdot 1}{2 \cdot 3}

4^{2} - 4 \cdot 3 \cdot 1 = 2

x_{1, 2} = \frac{- 4 \pm 2}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 4 + 2}{2 \cdot 3}, x_{2} = \frac{- 4 - 2}{2 \cdot 3}

x = \frac{- 4 + 2}{2 \cdot 3} : - \frac{1}{3}

x = \frac{- 4 - 2}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

x = - \frac{1}{3}, x = - 1

(9 x + 4)^{2} = 72 x + 25

5529 x^{2} - 18634 x + 8841 = 0

25 n^{2} - 15 n + 4 = 5 n

3 x^{2} + 1 = 7 x - 3

x^{2} - 8 x + 16 = 2

What are the solutions to the equation 3x^2+4x+9=8 ?
The solutions to the equation 3x^2+4x+9=8 are x=-1/3 ,x=-1
Find the zeros of 3x^2+4x+9=8
The zeros of 3x^2+4x+9=8 are x=-1/3 ,x=-1