What are the solutions to the equation 2x^2-10-8x=0 ?

The solutions to the equation 2x^2-10-8x=0 are x=5,x=-1

Find the zeros of 2x^2-10-8x=0

The zeros of 2x^2-10-8x=0 are x=5,x=-1

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2 x^{2} - 10 - 8 x = 0

x = 5, x = - 1

Solution steps

2 x^{2} - 10 - 8 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 8 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 2 ( - 10 )}{2 \cdot 2}

(- 8)^{2} - 4 \cdot 2 (- 10) = 12

x_{1, 2} = \frac{- ( - 8 ) \pm 12}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 12}{2 \cdot 2}, x_{2} = \frac{- ( - 8 ) - 12}{2 \cdot 2}

x = \frac{- ( - 8 ) + 12}{2 \cdot 2} : 5

x = \frac{- ( - 8 ) - 12}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

x = 5, x = - 1

4 x^{2} + 140 x - 296 = 0

x, x^{2} - y^{2} = a^{2}

- p^{2} + 5 p + 6 = - 2 p^{2}

(x - 64) (x + 64) = 0

x, 2 x^{2} + y^{2} = 4 C x

What are the solutions to the equation 2x^2-10-8x=0 ?
The solutions to the equation 2x^2-10-8x=0 are x=5,x=-1
Find the zeros of 2x^2-10-8x=0
The zeros of 2x^2-10-8x=0 are x=5,x=-1