What are the solutions to the equation y^2-7y=-12 ?

The solutions to the equation y^2-7y=-12 are y=4,y=3

Find the zeros of y^2-7y=-12

The zeros of y^2-7y=-12 are y=4,y=3

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y^{2} - 7 y = - 12

y = 4, y = 3

Solution steps

y^{2} - 7 y = - 12

Move

12

to the left side

y^{2} - 7 y + 12 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 12 = 1

y_{1, 2} = \frac{- ( - 7 ) \pm 1}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 7 ) + 1}{2 \cdot 1}, y_{2} = \frac{- ( - 7 ) - 1}{2 \cdot 1}

y = \frac{- ( - 7 ) + 1}{2 \cdot 1} : 4

y = \frac{- ( - 7 ) - 1}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

y = 4, y = 3

3 x^{2} = - 9 x + 2

x, x^{2} + y^{2} - 4 x - 2 y + 17 = 0

- 2 x^{2} - 3 x + 7 = 0

3 b^{2} - 7 b + 3 = 6

a, (a + b + c + d)^{2} = 4 (a + b) (c + d)

What are the solutions to the equation y^2-7y=-12 ?
The solutions to the equation y^2-7y=-12 are y=4,y=3
Find the zeros of y^2-7y=-12
The zeros of y^2-7y=-12 are y=4,y=3