What are the solutions to the equation 24pir-(9pi)/2 r^2=0 ?

The solutions to the equation 24pir-(9pi)/2 r^2=0 are r=0,r= 16/3

Find the zeros of 24pir-(9pi)/2 r^2=0

The zeros of 24pir-(9pi)/2 r^2=0 are r=0,r= 16/3

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24 π r - \frac{9 π}{2} r^{2} = 0

r = 0, r = \frac{16}{3}

Decimal Notation

r = 0, r = 5.33333 \dots

Solution steps

24 π r - \frac{9 π}{2} r^{2} = 0

Multiply both sides by

2

- 9 π r^{2} + 48 π r = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 48 π \pm ( 48 π ) ^{2} - 4 ( - 9 π ) \cdot 0}{2 ( - 9 π )}

(48 π)^{2} - 4 (- 9 π) \cdot 0 = 48 π

r_{1, 2} = \frac{- 48 π \pm 48 π}{2 ( - 9 π )}

Separate the solutions

r_{1} = \frac{- 48 π + 48 π}{2 ( - 9 π )}, r_{2} = \frac{- 48 π - 48 π}{2 ( - 9 π )}

r = \frac{- 48 π + 48 π}{2 ( - 9 π )} : 0

r = \frac{- 48 π - 48 π}{2 ( - 9 π )} : \frac{16}{3}

The solutions to the quadratic equation are:

r = 0, r = \frac{16}{3}

q^{2} - q - 10 = 2 q

4 y^{2} + 11 y + 3 = - 1

v, \frac{m v ^{2}}{r} = q v B

5 x^{2} + 14 x = x + 6

x, x^{2} (y^{2} - 4) = 4

What are the solutions to the equation 24pir-(9pi)/2 r^2=0 ?
The solutions to the equation 24pir-(9pi)/2 r^2=0 are r=0,r= 16/3
Find the zeros of 24pir-(9pi)/2 r^2=0
The zeros of 24pir-(9pi)/2 r^2=0 are r=0,r= 16/3