What are the solutions to the equation -0.03q^2+975=35q+263 ?

The solutions to the equation -0.03q^2+975=35q+263 are q=-3560/3 ,q=20

Find the zeros of -0.03q^2+975=35q+263

The zeros of -0.03q^2+975=35q+263 are q=-3560/3 ,q=20

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 0.03 q^{2} + 975 = 35 q + 263

q = - \frac{3560}{3}, q = 20

Decimal Notation

q = - 1186.66666 \dots, q = 20

Solution steps

- 0.03 q^{2} + 975 = 35 q + 263

Multiply both sides by

100

- 3 q^{2} + 97500 = 3500 q + 26300

Move

26300

to the left side

- 3 q^{2} + 71200 = 3500 q

Move

3500 q

to the left side

- 3 q^{2} + 71200 - 3500 q = 0

Write in the standard form

a x^{2} + b x + c = 0

- 3 q^{2} - 3500 q + 71200 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- ( - 3500 ) \pm ( - 3500 ) ^{2} - 4 ( - 3 ) \cdot 71200}{2 ( - 3 )}

(- 3500)^{2} - 4 (- 3) \cdot 71200 = 3620

q_{1, 2} = \frac{- ( - 3500 ) \pm 3620}{2 ( - 3 )}

Separate the solutions

q_{1} = \frac{- ( - 3500 ) + 3620}{2 ( - 3 )}, q_{2} = \frac{- ( - 3500 ) - 3620}{2 ( - 3 )}

q = \frac{- ( - 3500 ) + 3620}{2 ( - 3 )} : - \frac{3560}{3}

q = \frac{- ( - 3500 ) - 3620}{2 ( - 3 )} : 20

The solutions to the quadratic equation are:

q = - \frac{3560}{3}, q = 20

2 x^{2} - 4 x + 7

x, y = x^{2} + y

a, a^{2} - 2 ab + 4 b^{2} = 0

- 0.5 x^{2} + 50 x - 600 = 0

x, 0 = 1.47 x^{2} - 13.2 x + 12.86

What are the solutions to the equation -0.03q^2+975=35q+263 ?
The solutions to the equation -0.03q^2+975=35q+263 are q=-3560/3 ,q=20
Find the zeros of -0.03q^2+975=35q+263
The zeros of -0.03q^2+975=35q+263 are q=-3560/3 ,q=20